What does $\rho_k = 0$ mean?

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I'm reading Introductory Time Series with R in a section where the correlogram is discussed.

I'm confused by one of the statements:

If $\rho_k = 0$, the sampling distribution of $r_k$ is approximately normal, with a mean of $-1/n$ and a variance of $1/n$.

Earlier in the book the following are defined:

$$\rho_k = \frac{\gamma_k}{\sigma^2}$$

$$\gamma_k = E[(x_t - \mu)(x_{t+k} - \mu)]$$

My confusion is what $\rho_k = 0$ means. Should I read this as:

  • all the values of $\rho$ for each '$t$ and $t+k$' pair are zero? Or,
  • the sum of all values of $\rho$ for each '$t$ and $t+k$' pair are zero? Or,
  • something else?

I think the first one is correct. I.e. $\rho_1 = 0, \rho_2 = 0, ..., \rho_n = 0$

Simple answers preferred over complex ones.

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Under the null hypothesis there is no auto-correlation of order $k$ in the series, i.e., $\rho_k = 0$.