For instance, with $T \in \mathcal{L}$(Mat($2,2,\mathbb{C}$)) we are given that the minimal polynomial of $T$ is $p(z) = (z - 2i)(z + 7)^2$. I want to find the possible Jordan Forms pertaining to this $T$.
We know that the characteristic polynomial of $T$ is a polynomial multiple of the minimal polynomial, thus it is either $(z - 2i)^2 (z+7)^2$ or $(z - 2i) (z+7)^3$. So the eigenvalue $2i$ will have multiplicity = $1$ or $2$, and the eigenvalue $7$ will have multiplicity = $2$ or $3$.
However, I am left wondering how we can determine the block sizes for each eigenvalue given only the information that the minimal polynomial is $p(z) = (z - 2i)(z + 7)^2 \,$?
Given the minimal polynomial of $T$, in order to give the possible Jordan normal forms, the following facts are useful:
The minimal polynomial tells you what are the eigenvalues of $T$. In your case, there are two eigenvalues $\lambda_1=2i$ and $\lambda_2=-7$.
The sum of the sizes of all Jordan blocks corresponding to an eigenvalue $\lambda_i$ is its algebraic multiplicity, which is given by the characteristic polynomial of $T$.
The minimal polynomial divides the characteristic polynomial.
Given an eigenvalue $\lambda_i$, its multiplicity in the minimal polynomial is the size of its largest Jordan block.
So what can you tell about the Jordan form of $T$ according to what we have above?
You have exploited the third bullet point to give the possible characteristic polynomials:
$$ p_1(z)=(z-2i)^2(z+7)^2,\quad p_2(z)=(z-2i)(z+7)^3. $$
Now suppose it is $p_1$. ($p_2$ for your exercise.)
So you can conclude that the Jordan form for $T$ should be $$ \begin{pmatrix} -2i&&&\\ &-2i&&\\ &&-7&1\\ &&0&-7 \end{pmatrix}. $$