I've which decay constant is $9\times10^{-8}$ s$^{-1}$ so how to find half life (second) of this element? I asked my teacher but he doesn't have enough time to solve this. If anyone helps it would be great. $\ln2 = 0,693$
2026-04-28 12:21:33.1777378893
What happens half life (second) which Decay constant is $9 \times 10^{-8} s^{-1 }$
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This is the formula for radioactive decay.
(decay constant)=ln2/(half life)
So
$9\cdot 10^{-8}=\frac{0.693}{\left( half\; life \right)}$
$\left( half\; life \right)=\frac{0.693}{9\cdot 10^{-8}}$