How do you work out if a number (214) is a niven number with a base n? but it cant be just to base 10
the number needs to be divisible by the sum of its digits when written in base n
How do you work out if a number (214) is a niven number with a base n? but it cant be just to base 10
the number needs to be divisible by the sum of its digits when written in base n
$241$ is prime, so it's only divisible by the sum of its base $n$ digits if that sum is $1$ (which means $n = 241$) or $241$ (which means $n=1$).
EDIT: For $214 = 2 \cdot 107$, the other divisors are $2$ and $107$.
Base $107$: $214 = [2,0]$ with sum $2$.
Base $108$: $214 = [1, 106]$ with sum $107$.
Base $213$: $214 = [1, 1]$ with sum $2$.
It turns out those are the only possibilities (I wrote a program to try all bases from $2$ to $213$).