I am trying to calculate $(d\circ \iota_X) (fdx\wedge dy)(P,Q)$. Here $fdx\wedge dy$ is clearly a 2-form, and P,Q are vectors.
Is $(d\circ \iota_X) (fdx\wedge dy)(P,Q)$ simply equal to $df\wedge dx\wedge dy (X,P,Q)$? Or am I missing a step?
I am trying to calculate $(d\circ \iota_X) (fdx\wedge dy)(P,Q)$. Here $fdx\wedge dy$ is clearly a 2-form, and P,Q are vectors.
Is $(d\circ \iota_X) (fdx\wedge dy)(P,Q)$ simply equal to $df\wedge dx\wedge dy (X,P,Q)$? Or am I missing a step?
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