What is $\int\frac{x^2\sec^2 x}{1+x\tan x}\,\text{d}x$?

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$$\int\,\frac{x^2\sec^2 x}{1+x\tan x}\,\text{d}x$$

So, this problem has been disturbing me since a couple of days now. I just can't see it's solution. I tried substituting $\tan x=t$ or $x\tan x= t$ but am just not able to get the answer. Please help. Cheers!!