$$|\{n\in N:n\mid p^2q\}|$$ $p$ is an odd prime number, $q$ is a prime number and $p$ does not equal $q$.
I dont understand what they're asking me to find, is it to find a value of $n$ that divides into $p^2q$?
I need all the help i can get here, very new to this
thanks
What they ask for is in set-builder notation: the number of natural numbers $n$ such that $n$ divides $p^2q$, or the number of divisors of $p^2q$, or just $\tau(p^2q)$.
$p$ does not have to be an odd prime for us to figure this out, just that $p\ne q$. There are six divisors: $$1,p,p^2,q,pq,p^2q$$ So the required answer is 6.