What is the derivative of $\mathrm dI/ \mathrm dt$ , where $I =I_0 e^{-t/RC}$?

Question

What is $$\frac{\mathrm dI}{\mathrm dt}, \text{ where } I =I_0 e^{-t/RC}?$$ Any help please? Been learning derivatives for a day or two.

Answer 1

Assuming you mean $\frac{dI}{dt}$ and it should actually be $$ I(t)=I_0e^{-t/RC} $$ where $I_0$ is a constant (initial current?), then by the chain rule $$ I'(t)=I_0e^{-t/RC}(-t/RC)'=-\frac{I_0}{RC} e^{-t/RC} $$