Given an algebraic category, Birkhoff's Variety Theorem gives a categorical characterization of the full subcategories whose object-class forms a variety (i.e. can be defined by equations in the sense of Model Theory).
The theorem is often stated as being of fundamental importance to Universal Algebra. As far as its importance for metamathematical questions is concerned, this does not surprise me, as it describes a connection between Model Theory and Universal Algebra. But what about its “internal” importance for Universal Algebra? Suppose we are studying a certain class of objects in some algebraic category. In how far could it be useful to know whether this class forms a variety?
My question only concerns the one implication of Birkhoff's theorem of course. It is clear that the result that varieties are closed under the taking of products, subalgebras and homomorphic images has a wide range of possible applications. But what about the converse?
This may not be the best answer, but it is an interesting sort of application of Birkhoff's theorem.
Let's say you have some class $V$ of algebras which is defined "semantically" (e.g. as all the algebras arising from some construction), and you want to give an equivalent "syntactic" description (i.e. an axiomatization $T$). Classical examples of this include showing that the group axioms pick out the class of subgroups of permutation groups, or that the Boolean algebra axioms pick out the class of subalgebras of powerset algebras [note that I'm not claiming that Birkhoff's theorem is useful for these classical examples].
If you can show directly that $V$ is closed under the HSP operations, then you can conclude that some equational axiomatization $T^*$ exists, and this knowledge can actually help you prove that a particular equational axiomatization $T$ works.
How? Well, for example, it's clear that an algebra $A$ satisfies an equation if and only if every finitely generated subalgebra of $A$ satisfies the equation. So if you want to check that $A$ satisfies $T$ if and only if it's in $V$ (if and only if $A$ satisfies the mysterious $T^*$), then you can assume without loss that $A$ is finitely generated. And finiteness assumptions like this can be very useful.