$\Delta ABC$ exists in hyperbolic geometry. What is the maximum value for $m\angle A+m\angle B+m\angle C$?
2026-03-30 16:45:37.1774889137
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What is the largest possible sum of all the angle measures of a $\Delta$ in hyperbolic space?
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The area of a spherical triangle is given by $${\rm area}(\triangle)={\rm angle\ sum}-\pi\ ,$$ and for a hyperbolic triangle we have $${\rm area}(\triangle)=\pi-{\rm angle\ sum}(\triangle)\ .$$ Both formulas are a consequence of the famous Gauss-Bonnet theorem. It follows that in a hyperbolic triangle we have $${\rm angle\ sum}(\triangle)=\pi-{\rm area}(\triangle)\ .$$ As such triangles can have arbitrary small area $>0$ there is no hyperbolic triangle of maximal area, but we can say that the supremum of the angle sums is $\pi$. Note that small triangles of arbitrary shape can approximate this supremum.
$\pi- \epsilon$.
The sum of the angles of a hyperbolic triangle comes out to $\pi - Area(\Delta ABC)$, so by making the area close to zero, your angles will be close to $\pi$ (think of $\epsilon$ as a small constant).
On the other hand, by making a very large hyperbolic triangle, the angles approach zero and the sides are nearly parallel. (Try this in a model of hyperbolic space, like the Poincare disc.)