$$\lim_{x\to 0}\ x*[2sin\frac{1}{x}]=?$$
When I use the sandwich method, I get that the limit = 0. is that correct?
$$\lim_{x\to 0}\ x*[2sin\frac{1}{x}]=?$$
When I use the sandwich method, I get that the limit = 0. is that correct?
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Rewrite as:
$x [Sin \frac{1}{x}]=\frac {[sin{\frac{1}{x}]}}{\frac{1}{x}}$
Using L'Hopital rule we get:
$\lim_{x→0} x [Sin \frac{1}{x}]= \lim_{x→0}[ Cos \frac{1}{x}] $
$\ Cos x∈ \{-1, 1\}$
Therefore:
$\lim_{x→0} [Cos \frac{1}{x}]=0 $