Okay so either I'm integrating wrong or the book is wrong i'm trying to calculate the median of the given cumulative distribution function of $F(x) = x^2/16$ $for 0\le x \le4$ The answer in the book is 2.83
2026-03-27 02:02:55.1774576975
what is the median of this random variable?
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By definition, the median is the unique number $x$ for which $F(x)=1/2$, which gives $x=2\sqrt{2}$, which is approximated by $2.83$.