What is the supremum of $f(z)$?

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I know that supremum is the lowest upper bound and infimum is the biggest lower bound. Also according to the supremum axiom, every non-nempty set bounded above has a supremum. Put

$$‎f(z) = \frac{|‎\frac{\sin(z)+\sin(1)-\sin(z+1)}{2-2\cos(1)}|-‎\frac{1}{2}‎\sinh‎(|z|)-‎\cosh‎(|z|)+1 }{‎\frac{1}{\pi^2-1}‎‎‎‎‎\cosh‎‎(\pi|z|)-‎\frac{1}{\pi^2-1}-‎\cosh‎(|z|)+1},\;\;z\in\mathbb{C}\setminus\{0\}.‎$$

I know that $f(z)$ is bounded above for every $z\in\mathbb{C}\setminus\{0\}$. Now my question is finding the supremum of $f(z)$.To this end I tried to get limit but I could not succeed. I appreciate any help to this matter.