The theorem states:
The suspension map $\pi_{i}( S^{n})\rightarrow \pi_{i}(S^{n+1})$ is an isomorphism when $i<2n-1$ and a surjection when $i=2n-1$. In the case where $X$ is an $(n-1)$-connected CW complex, this holds for the suspension map $\pi_{i}(X)\rightarrow \pi_{i}(SX)$.
But what explicitly is this suspension map?
Suspension is a functor $\Sigma$ defined on the homotopy category of pointed topological spaces. It maps $[X,Y]$ to $[\Sigma X,\Sigma Y]$, by mapping an arrow $f:X\to Y$ to an arrow $\Sigma f:\Sigma X\to \Sigma Y$ (see below) and being homotopy invariant. Here the brackets denote homotopy classes of based maps.
Therefore it maps $\pi_n(X)=[S^n,X]$ to $[\Sigma S^n,\Sigma X]\cong [S^{n+1},\Sigma X] = \pi_{n+1}(\Sigma X)$.
You seem to ask for clarification concerning the explicit construction of the suspension functor, namely at the level of maps. I believe Arkowitz's explanation in "Introduction to Homotopy Theory" is very explicit, and in turn, complements Amitesh's answer (you can ignore the definitions of $c$ and $j$ as they are not relevant for our purposes):
Geometrically, you should picture $\Sigma f$ going from $\Sigma A$ to $\Sigma A'$, and being just $f$ at every horizontal slice, which is a time $t$.