$$\int_{-a}^{a}dx\, \theta(\sqrt{x}) = \,?$$
At this calculation, I can do anything in the range of $-a < x < 0$. How can I do that calculation?
$$\int_{-a}^{a}dx\, \theta(\sqrt{x}) = \,?$$
At this calculation, I can do anything in the range of $-a < x < 0$. How can I do that calculation?
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