Below is my derivation, and result is different from formula $(15)$. What is wrong with my matrix derivation?
They use that $M$ and $\Lambda$ are symmetric, so it becomes
$$\frac{\partial \epsilon}{\partial Q} = \Lambda(Q-X) + \Lambda^T(Q-X) + \mu MQ + \mu M^TQ = 2\Lambda(Q-X) + 2\mu MQ$$
and when requiring
$$\frac{\partial \epsilon}{\partial Q} = 0$$
for maximization, you can cancel the $2$s:
$$\Lambda(Q-X) + \mu MQ = 0$$
Your derivation is correct. Conclude your result using the fact that $\Lambda$ and $M$ are symmetric matrices.
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They use that $M$ and $\Lambda$ are symmetric, so it becomes
$$\frac{\partial \epsilon}{\partial Q} = \Lambda(Q-X) + \Lambda^T(Q-X) + \mu MQ + \mu M^TQ = 2\Lambda(Q-X) + 2\mu MQ$$
and when requiring
$$\frac{\partial \epsilon}{\partial Q} = 0$$
for maximization, you can cancel the $2$s:
$$\Lambda(Q-X) + \mu MQ = 0$$