I have tried reading a proof of the signature theorem but it is way beyond me, is there a way to motivate, in english, why anyone even started searching for such a formula? Why would one assume that the signature of a manifold had anything to do with pontrjagin numbers?
2026-03-26 01:12:38.1774487558
What motivated trying to express the signature of a manifold as a linear combination of pontrjagin numbers?
77 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
There are 1 best solutions below
Related Questions in ALGEBRAIC-TOPOLOGY
- How to compute homology group of $S^1 \times S^n$
- the degree of a map from $S^2$ to $S^2$
- Show $f$ and $g$ are both homeomorphism mapping of $T^2$ but $f$ is not homotopy equivalent with $g.$
- Chain homotopy on linear chains: confusion from Hatcher's book
- Compute Thom and Euler class
- Are these cycles boundaries?
- a problem related with path lifting property
- Bott and Tu exercise 6.5 - Reducing the structure group of a vector bundle to $O(n)$
- Cohomology groups of a torus minus a finite number of disjoint open disks
- CW-structure on $S^n$ and orientations
Related Questions in VECTOR-BUNDLES
- Compute Thom and Euler class
- Confusion about relationship between operator $K$-theory and topological $K$-theory
- Bott and Tu exercise 6.5 - Reducing the structure group of a vector bundle to $O(n)$
- Why is the index of a harmonic map finite?
- Scheme theoretic definition of a vector bundle
- Is a disjoint union locally a cartesian product?
- fiber bundles with both base and fiber as $S^1$.
- Is quotient bundle isomorphic to the orthogonal complement?
- Can We understand Vector Bundles as pushouts?
- Connection on a vector bundle in terms of sections
Related Questions in CHARACTERISTIC-CLASSES
- Passage in the proof of Chern-Weil method in John Roe's Elliptic operators book
- "Symmetry of trace" passage in the proof of Chern Weil.
- Proving that a form is horizontal in the Chern Weil method proof
- Chern-Weil homomorphism and Chern/Pontryagin/Euler class
- Chern classes, cohomology classes with real/integer coefficients
- prerequisite for reading characteristic classes
- On the proof of Poincaré dual of transversal intersection
- How does one introduce characteristic classes
- Applications of Chern class to gauge theories in physics
- First obstacle to triviality is orientability
Related Questions in COBORDISM
- Cobordisms and compactness
- Cobordism and Boundary Theorem (Guillemin-Pollack)
- Handle attachment and spin$^c$ structures
- Limitive result in constructing cobordisms for 3-manifolds
- Formal group law of complex cobordism
- Pontryagin-Thom construction references for homotopy groups of spheres
- Orientable double-cover of the Mobius strip
- Why is the $J$-homomorphism an isomorphism for $n=1$?
- Understanding Corollaries of the h-cobordism theorem
- Cobordant 1-manifolds are homologous?
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Find $E[XY|Y+Z=1 ]$
- Refuting the Anti-Cantor Cranks
- What are imaginary numbers?
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- How do we know that the number $1$ is not equal to the number $-1$?
- What are the Implications of having VΩ as a model for a theory?
- Defining a Galois Field based on primitive element versus polynomial?
- Can't find the relationship between two columns of numbers. Please Help
- Is computer science a branch of mathematics?
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- Generator of inertia group in function field extension
Popular # Hahtags
second-order-logic
numerical-methods
puzzle
logic
probability
number-theory
winding-number
real-analysis
integration
calculus
complex-analysis
sequences-and-series
proof-writing
set-theory
functions
homotopy-theory
elementary-number-theory
ordinary-differential-equations
circles
derivatives
game-theory
definite-integrals
elementary-set-theory
limits
multivariable-calculus
geometry
algebraic-number-theory
proof-verification
partial-derivative
algebra-precalculus
Popular Questions
- What is the integral of 1/x?
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- Is a matrix multiplied with its transpose something special?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- How to tell if a set of vectors spans a space?
- Calculus question taking derivative to find horizontal tangent line
- How to determine if a function is one-to-one?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- Is this Batman equation for real?
- How to find perpendicular vector to another vector?
- How to find mean and median from histogram
- How many sides does a circle have?
First one notes that the signature is a bordism invariant, additive, and multiplicative, hence defines $\sigma:\Omega \otimes \mathbb Q\to \mathbb Q$.
Next you note that every ring morphism from the oriented bordism ring $\Omega \to \mathbb Q$ factors through $\Omega \otimes \mathbb Q$. But we know that on the latter space the Pontryagin classes are a complete invariant. That means that we should able to write down any such morphism in terms of these classes.
Lastly, one computes necessary conditions on how a ring morphism looks like, and one obtains that these are always given by a multiplicative sequence (plugging in the Pontryagin classes), which are in correspondence to power series. This implies that the signature needs to come from a power series.
Now, verifying the power series for the signature is easier (and more mysterious!) than you think. This is just done using a trick from complex analysis called the residue theorem.