What's the fourier transform of $\cos(bt)u(t)$?

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I have been trying to find the Fourier Transform of $\cos(bt).u(t)$

I applied the definition $$\int_{-\infty}^{\infty} \cos(bt).u(t).e^{-jwt} dt = \int_{0}^{\infty} \cos(bt).e^{-jwt} dt = \int_{0}^{\infty} \frac{e^{jbt} + e^{-jbt}}{2} .e^{-jwt} dt$$ Which simplifies to $$ \frac{1}{2} \int_{0}^{\infty} e^{j(b-w)t} + e^{-j(b+w)t}dt$$

But now I'll need to compute $e^\infty$ which isn't computable

How to handle this case?