What will the value of determinant of matrix $A=\pmatrix{1&3&4\\5&2&a\\6&-2&3}$ be change if we change $a$ to $a+2$.
This is an easy problem because $|A|=-127+20a$ and if we did that changing, we would get $-87+20a$. My question here is:
Can we do this request by doing another way? Where does that $+40$ come from regarding the whole entries of the matrix? Thanks
The determinant, is after all a multilinear map on the column / row vectors.
Therefore, $$ \det\begin{pmatrix} 1&3&4 \\ 5&2&(a+2) \\6&-2&3 \end{pmatrix} = \det\begin{pmatrix} 1&3&4 \\ 5&2&a \\6&-2&3 \end{pmatrix} +\det\begin{pmatrix} 1&3&0 \\ 5&2&2 \\6&-2&0 \end{pmatrix} $$
The determinant of the second matrix is?
If I changed $2$ to $3$ or $4$ or $b$, the answer would be?