There are cases when the multiplicative group $\mathbb{Z}_n^*$ is a cyclic group. But my question is, for what $n$ does $\mathbb{Z}_n^*$ have prime order?
Or equivalently, for what $n$ is the Euler totient function of $n$ equal to a prime number?
There are cases when the multiplicative group $\mathbb{Z}_n^*$ is a cyclic group. But my question is, for what $n$ does $\mathbb{Z}_n^*$ have prime order?
Or equivalently, for what $n$ is the Euler totient function of $n$ equal to a prime number?
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$\phi(2^k)=2^{k-1}$ is even for $k>1$,
$\phi(p^k)=(p-1)p^{k-1}$ is even for odd prime $p$ and $k\ge1$,
and $\phi$ is multiplicative, so $\phi(n)$ is even for $n>2$.
Therefore, $\phi(n)$ is $2$ or a multiple of $2$ (not prime) for $n>2$.
$\phi(n)=2$ only for $n=3, 4$ or $6$.