When $n\mid\sum_{k=1}^{n}\phi (k)$

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Consider this function.

$$f(n)=\sum_{k=1}^{n}\phi (k)$$

where $\phi (k)$ is the Euler's totient function. I'm wondering are there infinitely many $n$ such that $n\mid f(n)$? For $n\leq 4000$ only solutions are $1, 2, 5, 6, 16, 25, 36, 249, 617, 1296$