When the natural homomorphism from $Aut(G)$ to $Aut(G/N)$ is onto?

97 Views Asked by At

For the last few days, I have been working on a bunch of group theory problems and I am stuck with one question that came into my mind. My level is up to an introductory course in group theory and maybe the answer to my question is known, but I do not know where to find its solution. My question is the following:

Let $N$ be a characteristic subgroup of a group $G$. We know that if $\sigma: G \rightarrow G$ is an automorphism then there is an automorphism $\sigma^{\ast}: G/N \rightarrow G/N$ given by $gN \mapsto \sigma(g)N$. Thus, we have an homomorphism $\rho: Aut(G) \rightarrow Aut(G/N)$. My question is when the homomorphism $\rho$ is surjective. Is there a necessary and sufficient condition so that $\rho$ is surjective? Please help me, I am not able to solve this question.

1

There are 1 best solutions below

0
On

Derek is right, nothing really can be said here in general. The same question has been asked twice on MO a few years ago:

Also here on math.SE:

A concrete counterexample can be found here:

The paper Lifting Automorphisms of Quotients by Central Subgroups by Ben Kane and Andrew Shallue deals with the case that $N$ is central.