I'm trying to figure out where $f(z) = z^k \Re(z)$ is complex differentiable. I've tried to express $z$ as $z=x+yi$, but I can't figure out how to apply the Cauchy-Riemann equations.
2026-03-27 08:16:40.1774599400
Where is $f(z) = z^k \Re(z)$ complex differentiable?
53 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in COMPLEX-ANALYSIS
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