Where is $f(z) = z^z$ holomorphic?

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I've been messing around with this complex function visualizer: davidbau.com/conformal/

The picture it shows for $f(z) = z^z$ is pretty crazy, so I was wondering: is this function holomorphic?

In the real case we'd find the derivative of $f(x) = x^x$ by taking the log of both sides and applying the chain rule. Can we still do that here?

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$z^z = \exp(z\log z)$ is multi-valued. Choosing any specific branch of $\log$ gives a branch of $z^z$ which is holomorphic where $\log$ is.

For example, taking $\log$ as the principal branch, we get a $z^z$ which is holomorphic everywhere except at the negative real axis.