Which properties does the polynomial ring $\mathcal{R}[X]$ inherit from the ring $\mathcal{R}$?

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I've learned that

  • $\mathcal{R}$ is commutative → $\mathcal{R}[X]$ is commutative

  • $\mathcal{R}$ has no zero divisors → $\mathcal{R}[X]$ has no zero divisors

  • $\mathcal{R}$ is unital$\mathcal{R}[X]$ is unital

  • $\mathcal{R}$ is factorial$\mathcal{R}[X]$ is factorial

  • $\mathcal{R}$ is Noetherian$\mathcal{R}[X]$ is Noetherian

Which other properties of a polynomial ring are inherited from its coefficient ring?


List of properties from the comments and answers below (without credits):

  • $\mathcal{R}$ is reduced$\mathcal{R}[X]$ is reduced

  • $\mathcal{R}$ is Abelian$\mathcal{R}[X]$ is Abelian

  • $\mathcal{R}$ is nonsingular$\mathcal{R}[X]$ is nonsingular

  • $\mathcal{R}$ is 2-primal$\mathcal{R}[X]$ is 2-primal

  • $\mathcal{R}$ is Armendariz$\mathcal{R}[X]$ is Armendariz

  • $\mathcal{R}$ has characteristic $n$$\mathcal{R}[X]$ has characteristic $n$

  • $\mathcal{R}$ has finite Krull dimension$\mathcal{R}[X]$ has finite Krull dimension

  • $\mathcal{R}$ has finite global homological dimension$\mathcal{R}[X]$ has finite global homological dimension

2

There are 2 best solutions below

0
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A few examples:

"has finite Krull dimension"

"has finite global homological dimension"

"has characteristic $n$", for any $n$

4
On

The current contents of DaRT yielded this list:

Properties passing to a polynomial ring of one variable:

nonsingular ring, 2-primal ring, reduced, Armendariz, Abelian, right Noetherian.

Properties not passing to the polynomial ring of one variable:

semicommutative, right principally injective, quasi Frobenius, right coherent, Boolean, periodic, Goldman domain, right Artinian, right principal ideal domain/ring, right self-injective, simple, von Neumann regular, right primitive, semisimple.

This is far from complete, of course, but I'm adding to it as I go.

I think I'm probably missing several of the nice commutative algebraic-geometry flavor rings from the first list, but I won't guess without confirmation.