Why are quadratic forms that satisfy these conditions isotropic?

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I'd like to know why all quadratic forms satisfy the following:

1) If $F$ is an algebraically closed field, for example, the field of complex numbers, and $(V, q)$ is a quadratic space of dimension at least two, then it is isotropic.

And:

2) If $F$ is the field $Q_p$ of p-adic numbers and $(V, q)$ is a quadratic space of dimension at least five, then it is isotropic.

Any insight on these two is greatly appreciated.

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On the first one, from Cassels. He has characteristic not two. He does not say that all forms can be diagonalised over a field, he says that there is a normal basis. We use the polarization identity to get an inner product $\phi,$ a normal basis has $\phi(u_i, u_j) = 0$ when $i \neq j.$ Therefore the form applied to a vector becomes $\sum a_i x_i^2.$ Over an algebraically closed field, we can take all but the first two $x_i$ zero, then take $x_2 = 1,$ and solve for $x_1$ in $a_1 x_1^2 + a_2 = 0.$

The dimension 5 bit is a longer story. I recommend Cassels because he is focused on the rational numbers and the rational integers, he does isotropy for the $p$-adics in great and understandable detail. This includes tables for the Hilbert norm residue symbol, pages 43 and 44, with which the isotropy results are proved, pages 58-60 primarily. Your question is Lemma 2.7, page 60. The proof is pigeonhole on the $p$-adic squareclasses