I have observed that the distance of any $n\in\Bbb N$ to its closest non-adjacent (smaller or greater than $n$ at a distance $\not=$ 1) coprimes is always a prime number.
Def:
$\forall n\ \exists\ c_{left}\ /\ (c_{left},n)=1\ ,\ c_{left}\lt n\ ,\ (d_{left}=n-c_{left})\gt 1\ \land\ \not \exists\ k\ \ 1 \lt (n-k) \lt (n-c_{left}) \land (k,n)=1$
$\forall n\ \exists\ c_{right}\ /\ (c_{right},n)=1\ ,\ c_{right}\gt n\ ,\ (d_{right}=c_{right}-n)\gt 1\ \land\ \not \exists\ k\ \ 1 \lt (k-n) \lt (c_{right}-n) \land (k,n)=1$
So it seems that:
$\forall n\ d_{left},d_{right} \in \Bbb P$
E.g.:
$n=16, c_{left}=13, c_{right}=19, d_{left}=3 , d_{right}=3$
$n=892290, c_{left}=892279, c_{right}=892301, d_{left}=11 , d_{right}=11$
This is a very brute-force Python code, just in case somebody would like to try or modify it:
def coprimes():
from sympy import gcd
from gmpy2 import is_prime
print("Result " + "\t" + "n" + "\t" + "From" + "\t" + "c" + "\t" + "d")
for n in range (1,1000000):
j=n-2
while not gcd(n,j)==1:
j=j-1
if is_prime(n-j):
print("OK" + "\t" + str(n) + "\t" + "Left" + "\t" + str(j) + "\t" + str(n-j))
else:
print("ER" + "\t" + str(n) + "\t" + "Left" + "\t" + str(j) + "\t" + str(n-j))
j=n+2
while not gcd(n,j)==1:
j=j+1
if is_prime(j-n):
print("OK" + "\t" + str(n) + "\t" + "Right" + "\t" + str(j) + "\t" + str(j-n))
else:
print("ER" + "\t" + str(n) + "\t" + "Right" + "\t" + str(j) + "\t" + str(j-n))
coprimes()
It also might be possible that every prime $p$ could appear as a distance $d_{left}$ or $d_{right}$, so every prime is a distance from a given $n$ to its $c_{left}$ or $c_{right}$ closest non-adjacent coprime.
I do not understand the reasons behind this, just can guess that somehow might be related with the probabilities of two numbers of being non-adjacent coprimes and some inference from the PNT, so I would like to ask the following questions:
Does it make sense that according to the definition or coprimality, these distances were always prime numbers?
Is there a counterexample of them?
Is it a trivial property?
Any hint is very appreciated. Thank you!
Take $n$ and $a$ such that $\gcd(n,a) = 1$. Then we know that
$$\gcd(n+a,n) = 1, \gcd(n+a,a) = 1$$
By employing the Euclidean algorithm for division.
For any given number, the smallest integer coprime to it is a prime number (which will give the nearest non-adjacent coprime number by addition). This is easy to see; if an integer is coprime to some number, then it must be coprime with all factors of that number.
This means that the distance to the nearest non-adjacent coprime is simply the smallest $p$ that does not divide $n$.
To see the other direction, suppose we had some number other than that satisfying this property. If it is not coprime to $n$, then it fails to generate a coprime. If it is coprime, then its factorization yields a smaller coprime prime, a contradiction.