Why are we interested in total variation and how does it tie into its integral definition?

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I am studying measure theory and had a few questions. In the text I am using, it defines total variation of a measure $\nu$ as

$$|\nu| = \nu^+ + \nu^-$$ My first question is why are we interested in this quantity to begin with? Secondly, the text claims that the above implies $\nu$ is of the form $\nu(E) = \int_E f d|\nu|$, for any measurable set $E$. I cannot see how this integral definition follows the total variation definition. Lastly, the text claims the inequality $|\nu(E)| \leq |\nu|(E)$ is obvious, but I cannot quite see how. One last question I have is one of notation. I see notation such as $g(\frac{d\nu}{d\mu})$, what does this mean exactly?

Thank you.

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(1) Why are we interested in the total variation?

Firstly, because of (2) and (3), below. We can often prove things about signed measures using this.

(2) Why is $\nu(E) = \int_E f d|\nu|$?

Hahn decomposition.

(3) Why is $|\nu(E)| \leq |\nu|(E)$?

Use your solution to (2).

(4) I doubt you often see $g(\frac{d\nu}{d\mu})$, that is a function $g$ evaluated on a Radon-Nikodym derivative. But you do often see $g\;\frac{d\nu}{d\mu}$, that is a function $g$ multiplied by a Radon-Nikodym derivative.