Why coefficient in a Cartan Matrix must be integers?

102 Views Asked by At

A generalized Cartan matrix is a square matrix $ A=(a_{ij})$ with integral entries such that

  • For diagonal entries,$a_{ii}=2$.
  • For non-diagonal entries, $a_{ij}\leq 0$.
  • $a_{ij}=0$ if and only if $a_{ji}=0$
  • $A$ can be written as $DS$, where $D$ is a diagonal matrix, and $S$ is a symmetric matrix.

From the Cartan Matrix I can recover a semisimple Lie algebra. What I'm wondering is what goes wrong if the coefficients are non integers but real? I know in Lie theory this cannot happen but I do not really grasp what goes wrong in the definition of the Lie algebra...

1

There are 1 best solutions below

7
On

The reason is related to the root system of the Lie Algebra. The entries of the Cartan matrix are defined as;

$$a_{ij}=2{(r_i,r_j)\over(r_j,r_j)}$$

Where $r_i$ are the simple roots$\space(\Phi)$ of the Lie algebra. As it turns out the simple roots have the property that if $\alpha,\beta \in \Phi$ then the projection of $\alpha$ onto $\beta$ is always an integer or a half integer multiple of $\beta$.

This will property will obviously always cause $a_{ij}$ to be an integer.