I'm so confused on how we can have a 2x3 matrix A, multiply it by a vector in $\Bbb R^3$ and then end up with a vector in $\Bbb R^2$. Is it possible to visualize this at all or do I need to sort of blindly accept this concept as facts that I'll accept and use? Can someone give a very brief summarization on why this makes sense? Because I just see it as, in a world (dimension) in $\Bbb R^3$, we multiply it by a vector in $\Bbb R^3$, and out pops a vector in $\Bbb R^2$.
Thanks!

For the moment don't think about multiplication and matrices.
You can imagine starting from a vector $(x,y,z)$ in $\mathbb{R}^3$ and mapping it to a vector in $\mathbb{R}^2$ this way, for example: $$ (x, y, z) \mapsto (2x+ z, 3x+ 4y). $$
Mathematicians have invented a nice clean way to write that map. It's the formalism you've learned for matrix multiplication. To see what $(1,2,3)$ maps to, calculate the matrix product $$ \begin{bmatrix} 2 & 0 & 1 \\ 3 & 4 & 0 \end{bmatrix} \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix} = \begin{bmatrix} 5\\ 11 \end{bmatrix}. $$
You will soon be comfortable with this, just as you are now with whatever algorithm you were taught for ordinary multiplication. Then you will be free to focus on understanding what maps like this are useful for.
Edit in response to a comment.
No, this does not make $(5,11)$ "look like" $(1,2,3)$. Here is a toy example that suggests where you might find this kind of calculation. Suppose you run a business that builds three products. Call them A, B and C. To make an A you need $2$ widgets and $3$ gadgets. To make a B you need just $4$ gadgets. For a C you need just a single widget. How many widgets and gadgets should you order to make $1$ A, $2$ B's and $3$ C's? The matrix product above provides the answer. You could also use that $2 \times 3$ matrix to figure out what orders you might fill if you knew how many widgets and gadgets you had in stock.
Matrices are helpful in geometry too. In a linear algebra course you learn how to see that when you use the matrix $$ \begin{bmatrix} 3 & -1 \\ -1 & 3 \end{bmatrix} $$ to map the coordinate plane (pairs of numbers) to itself what you have done is stretch circles centered at the origin into ellipses by changing the scales along the diagonal lines $y=x$ and $y=-x$ m