Why is $1/z$ analytic at infinity?

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I was given this proof:

Let $w(z)=1/z$, so $w$ maps origin to inifinity and infinity to origin.

Consider $f(z) = z$. It has no singularities in finite $z$-plane.

So $f(w) = 1/w$ has a pole at the origin of $w$-plane, which is at infinity in the $z$-plane.

$f(z)=1/z$ has a pole at origin.

So $f(w) = w$ is analytic at $w=0$.

Therefore $1/z$ is analytic at infinity.

I do not understand this proof at all!