I am reading proof of Brauer's theorem and I came across this result that any element of $rad(kG)$ is nilpotent. Why is this true?
$rad$ is Jacobson radical and $kG$ is group algebra over field $k$. Further $G$ is finite and $k$ is splitting field of $G$.
2026-04-08 09:06:11.1775639171
Why is any element in $rad(kG)$ nilpotnet?
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