There exists an $X\in A$ such that $P(X)$. When $A$ is the empty set then this statement is false because there is nothing in $A$ that when plugged in for $X$, makes $P(X)$ come out True.
However, when the quantifier is the universal one, meaning "For all $X\in A$" (which is the empty set), then the statement is true !!
How is that ? .. Because by the reasoning in the first statement, there are not any values of $X$ that makes $P(X)$ come out True.
I'm missing something !!
(I'm studying Electrical Engineering and self studying velleman's how to prove it and the quantifiers are already kicking my butt so simplify the answers for me if possible :))
The negation of the statement "for all $x\in X$, $P(x)$ holds" is "there exists $x\in X$ such that $P(x)$ does not hold". Well, then if $X$ is empty, then there is not a single $x\in X$ such that $P(X)$ is not true, and thus it is indeed true that for all $x\in X$, $P(X)$ is true.
The confusing part is that in general the validity of a statement of the form $\forall x\in X: P(X)$ does not imply the existence of a single $x\in X$ for which $P(X)$ holds. It only states that if $x\in X$ then $P(x)$ holds.
You can also think of it this way: Suppose I claim that everything in a box in front of you is pink. Can you sue me if you open it up and see a banana in there? Sure, the banana is yellow, so the judge will rule in your favor. But, can you sue me if you open up the box and see nothing at all in there? Well, no, you have nothing to complain about: everything in the box is indeed pink since nothing in it is not pink.