Why is $\Im((2 - i) z - 5 i)=2 \Im(z) - \Re(z) - 5$?
What happens with the real parts in $\Im(\cdot )$?
2026-04-12 15:12:59.1776006779
Why is $\Im((2 - i) z - 5 i)=2 \Im(z) - \Re(z) - 5$?
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Lert $z=x+iy$ then $$(2-i)(x+iy)-5i=2x+y+i(2y-x-5)$$