Peano arithmetic defines multiplication recursivly as:
$$\begin{gather}a\cdot0=a\\a\cdot S(b)=a+(a\cdot b)\end{gather}$$
Why is this not possible in Presburger arithmetic?
Peano arithmetic defines multiplication recursivly as:
$$\begin{gather}a\cdot0=a\\a\cdot S(b)=a+(a\cdot b)\end{gather}$$
Why is this not possible in Presburger arithmetic?
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