The integral in question is this:
$$\frac{1}{2}\int_0^{2\pi} [\cos^{-1}(\sin x)]^2~dx$$
The Mathematica code is
Integrate[(Acos[Sin[x]])^2/2, {x, 0, 2 Pi}]
Attempting this with Mathematica appears to be fruitless. It won't even do a numerical integration. WolframAlpha, however, deftly provides
$$\frac{1}{2}\int_0^{2\pi} [\cos^{-1}(\sin x)]^2~dx=\frac{\pi^3}{3}\approx 10.335$$
However, WA also declares a step-by-step solution is unavailable.
Incidentally, I know that the WA solution is correct because I have verified it numerically.
Well, because Mathematica is a programming language and has a defined syntax. The function is called
ArcCosand not Acos: