Why is the following function inside the integral $\int_E\frac{y}{x} e^{-x}\sin x\; d\mu$ measurable where $\mu$ is the product measure on $R$ with itself and $ E = \{ (x,y) : 0 \leq y \leq \sqrt{x}\}$?
2026-04-13 04:24:43.1776054283
Why is the following function $\int_E\frac{y}{x} e^{-x}\sin x\;d\mu$ measurable?
24 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in REAL-ANALYSIS
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