Why is the signature of a manifold homotopy invariant?

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I'm going through some applications of Poincaré duality for de Rham cohomology in Greub's Connections, Curvature and Cohomology. I was wondering about the homotopy invariance of the signature of a compact oriented $4k$-dimensional manifold and found this old question. In this case the signature $\mathrm{sig}(M)$ of $M$ is defined as $\mathrm{sig}(M):=\mathrm{sig}(P_{M}^{2k})$ where the non-degenerate symmetric bilinear form $$P_{M}^{2k}:H^{2k}(M)\times H^{2k}(M)\to \mathbb{R}$$ is given by $$([\alpha],[\beta])\mapsto \int_{M}\alpha\wedge\beta$$

I cannot seem to understand why the signature is a homotopy invariant, as stated in the first answer of the aforementioned question.

Any help would be appreciated.

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The definition you've given for the signature is phrased in terms of de Rham cohomology and is indeed not obviously homotopy invariant. However, the pairing you've given has a "lift" to singular cohomology: $([\alpha],[\beta]) \rightarrow \langle [\alpha] \cup [\beta], [M] \rangle$. Up to a sign, homotopy equivalences of compact manifolds always preserve the fundamental class, and so this definition of the bilinear form is a homotopy invariant, up to a sign.