I'm reading this textbook question and I'm confused as to why this answer is in radians and not degrees. How did that happen?
Why is this answer in radians and not degrees?
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The set of trig differentiation rules pretty much everyone uses is for the radians version of the trig functions. We use radians because they make the differentiation and integration of trig functions come out without ugly constants.
You could write a set of differentiation rules for "trig function in degrees" but then every rule contains an ugly extra constant. We can derive the degrees rule by applying the shortcut chain rule* to the corresponding radians rule. For example for than tan function (using $_{deg}$ for the degrees version of a trig function and $_{rad}$ for the radians version of a trig function).
$$\frac{d}{dx}\tan_{deg}{x} = \frac{d}{dx}\tan_{rad}\left({\frac{\pi}{180}x}\right) = \frac{\pi}{180}\sec_{rad}^2\left({\frac{\pi}{180}x}\right)= \frac{\pi}{180}\sec_{deg}^2x$$
But altogether it's easier to do trig calculus with radians and if necessary convert to degrees after all the calculus work is over.
* differentiate with respect to the bracket, then multiply by the derivative of the inside of the bracket.

If the question is about "why we use radians instead of degrees in calculus", look at following thread: Why do we require radians in calculus?