Definition of antisymmetric binary-relation is
$$\forall a,b\in\mathrm{A},\left[ \left(aRb\wedge bRa\right)\rightarrow\left(a=b\right)\right].$$
Let $\mathrm{A}=\left\{a\mid a\in\mathbb{R}\right\}$, and the relation set $R=\left\{\left(a,b\right)\mid a,b\in\mathbb{R}\wedge a\text{ is odd}\wedge b\text{ is even}\right\}.$
And $R$ is a antisymmetric binary-relation on $\mathrm{A}$. However, I don't understand.
For example, $2R2$ is false and $2=2$ is true. Then the logical expression becomes $\mathrm{F}\wedge\mathrm{F}\rightarrow\mathrm{T}$.
What am I missing? Is my concept on logical expression wrong?
Your evaluation that the antisymmetry condition has, in this case, a false antecedent and a true consequent is correct. But remember that a conditional will only be false if those truth values are the other way around; if you have $\mathbf{T}\to\mathbf{F}$. In this case, for antisymmetry to fail, we'd need an $x,y$ with $xRy\wedge yRx\wedge x\neq y$. But then both $x$ and $y$ would need to be both even and odd, which none are (much less two are), so no contradiction of antisymmetry is possible here.