Why is this not a proof of Schroeder-Bernstein?

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We can show that if $f: A \rightarrow B$ is injective then $|A| \leq |B|$ and if $g: B \rightarrow A$ is injective then $|B| \leq |A|$ so $|A| = |B|$. By the definition of having equal cardinality, there exists a bijection between $A$ and $B$.

Whenever a textbook proves the theorem, however, a more complicated proof is shown. I must be missing something.