I am reading in the Visual Group Therapy book that the above equation is unsolvable algebraically. What are other ways to solve this if not through algebra?
2026-04-13 11:47:03.1776080823
On
Why is $x^5 + 10x^4 -2$ unsolvable?
145 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
There are 2 best solutions below
0
On
There are many ways to estimate the roots of a polynomial (which I assume you are talking about). A typical method is to solve them numerically, say using Newton's method. There are other numerical schemes, but I'd argue that this is the most elementary one - usually taught in a first calculus course or definitely in a first numerical analysis course.
More generally, I believe Newton's method falls under something known as fixed point iteration. On this page, you'll find other techniques that can be used to estimate roots of an equation.
The roots of $x^5+10x^4-2=0$ can be computed approximately by various numerical methods.
They are three real roots : $x\simeq -9.9998 \quad;\quad -0.68063\quad;\quad 0.658168$
and two complex roots $x\simeq 0.0111307\pm 0.66809\,i $.
$x^5+10x^4-2=0$ is a quintic equation.
In general (except particular cases) the quintic equation cannot be solved in terms of a finite number of elementary functions (Abel and Galois theory). But it is solvable in terms of special functions, namely the Jacobi theta functions.
http://mathworld.wolfram.com/QuinticEquation.html