If $a \in (1/2,1)$ then $x(t):=|t|^a$ is not element of $D$ but $x^2=0$ in *$R$.
Why is it so?
Thanks.
2026-02-23 08:25:55.1771835155
Why is $x(t):=|t|^a$ not an element of $D$? (Synthetic Differential Geometry)
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