If there is an upper bound $a$ of a set $A$, and an upper bound $b$ of the set $A$ and $b>a$, why doesn't that mean that only $b$ is the upper bound of the set since it's "more upper" than $a$?
2026-04-06 08:00:26.1775462426
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Why isn't upper bound unique?
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An upper bound of a set $A$, by definition, is simply
An element that is larger than (or equal to) all elements of $A$.
So, for example, if $A=[0,1]$, then $2$ is an upper bound of $A$, because we can say that $2$ is larger or equal to all elements of $[0,1]$. Also, $3$ is an upper bound of $A$, and so is $4$ and several other numbers.
By your logic, since for any $a$ which is an upper bound of $A=[0,1]$, the number $b=a+1$ is also an upper bound for $A$, then $A$ has no upper bound because no number us "more upper" than all other numbers.
I think you may be confused with the terms UPPER BOUND and LEAST UPPER BOUND.
For more information on the latter term, refer to this Wikipedia page.