Why $PGL(2, 9)$ is not isomorphic to $S_6$?

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How can I show that $PGL(2,9)$ is not isomorphic to $S_6$?

My primary idea is to compare the size of conjugacy classes of two well-chosen elements in these groups. Is there another simpler approach?

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Let $\alpha$ be a generator of group $\mathbb F^*_9$. Now if consider the matrix $A=\hbox{diag}(1, \alpha)$ in $PGL(2,9)$ we have $\hbox{ord}(A)=8$, since $\hbox{ord}(\alpha)=8$. But there isn't any element of order $8$ in the symmetric group $S_6$. So these two groups can not be isomorphic.