I have a question regarding to part$(b)$ in the problem below:
" Let $V$ be a finite-dimensional vector space over the field $F,$ and let $B$ be a bilinear form on V.
$(b)$ Suppose $\operatorname{char}(F) \neq 2.$ $B$ is said to be skew-symmetric if $B(v_1, v_2) = -B(v_2, v_1)$ for all $v_1, v_2 \in V.$ Prove that if $B$ is skew-symmetric then its matrix (with respect to any basis) is skew-symmetric."
Why the author is excluding the field of characteristic $2$? could anyone answer this question to me please?
If the characteristic is 2, then $-1=1$ and signs make no sense. It is not reasonable to talk about skew-symmetricity in that case.