I understand how the logistic differential equation (disregarding the Malthusian parameter)
$\frac{dN}{dt}=KN(A-N)$ where A is the carrying capacity
produces the graph that it does, however, I was wondering why this differential equation is a natural choice when modeling the growth of things with a carrying capacity i.e. how does the existence of a carrying capacity and growth based on the current "population" lead to this differential equation? Likewise, why do curiosities such as the rate of growth is at its maximum when $N=\frac{A}2$ arise?
The solution to $$\frac{dN}{dt}=kN(A-N)$$ is $$ N(t) = \frac {AN(0)}{N(0)+(A-N(0)e^{-kt}}$$
The solution satisfies all the requirements of a population which starts at $N=N(0)$ and has the carrying capacity of $A.$
The difference between the carrying capacity and the population is decreasing very slowly as population approaches its carrying capacity.
The reason for the fastest growth at $N=A/2$ is that this point is where the second derivative of $N$ is zero.
That is an inflection point where the first derivative attains its maximum.
Note that $$\frac{d^2N}{dt^2}=k(A-2N)$$ which is zero at $N=A/2.$