Without expanding,prove that: $$\left| \begin{matrix} 3&4&5 \\ 15&21&26 \\ 21&29&36 \\ \end{matrix}\right|=0$$
My Attempt:
$$L.H.S.= \begin{vmatrix} 3 & 4 & 5 \\ 15 & 21 & 26 \\ 21 & 29 & 36 \\ \end{vmatrix} $$ Packing common "$3$" from the first column: $$=3 \begin{vmatrix} 1 & 4 & 5 \\ 5 & 21 & 26 \\ 7 & 29 & 36 \\ \end{vmatrix} $$
Row3=Row2+2*Row1. Hence, determinant is zero.