Working out automorphism groups of algebraic varieties

82 Views Asked by At

I came across the notion of the automorphism group of an algebraic variety. I was unable to calculate those groups for very basic examples, such as the sphere and the circle.

Is there any intuitive way to deal with and work out such examples?

1

There are 1 best solutions below

2
On BEST ANSWER

I'll assume we're working over $\mathbb{C}$ for simplicity - I'll also assume that the "circle" you are talking about are the varieties $$ X = V(x^2 + y^2 - z^2) \subset \mathbb{P}^2$$

Recall that the rational map $\mathbb{P}^1 \to X : [u,v] \mapsto [u^2 - v^2, 2uv, u^2 + v^2]$ is in fact an isomorphism.

Thus $\operatorname{Aut}(X)$ is isomorphic to $\operatorname{Aut}(\mathbb{P}^1)$.

Fact: The automorphism group of $\mathbb{P}^1$ is $PGL(1, \mathbb{C}) = GL_2(\mathbb{C})/\mathbb{C}^*$ where a $2\times 2$ matrix acts in the obvious way (N.B. these are the Mobius transformations).

You can probably find a proof of this in multiple places. Hartshorne I Ex 6.6 will walk you through a proof.

In general (Hartshorne II Example 7.1.1) one can show that $\operatorname{Aut}(\mathbb{P}^n_k) = PGL(n, k)$.