Write (1 2 3 4 5 6 7) as a product of 3-cycles

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It's not necessarily disjoint. I know how to work the other way around but get stuck trying to do this process.

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$(1\ 2\ 3)(1\ 4\ 5)(1\ 6\ 7) $

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$(1\ 2\ 3\ 4\ 5\ 6\ 7)=(1\ 2\ 3)(3\ 4\ 5)(5\ 6\ 7)$